TwoWheelFiend

January 10, 2012, 09:14 AM

just wondering. I should of listened to my math teachers when they told me id need math later in life.

anyone have any idea?

anyone have any idea?

TwoWheelFiend

January 10, 2012, 09:14 AM

just wondering. I should of listened to my math teachers when they told me id need math later in life.

anyone have any idea?

anyone have any idea?

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tyeo098

January 10, 2012, 09:54 AM

First you find the time in flight:

vf=vi-at

0=940sin(45)-9.8t (assuming SS109 projectile from a 20 in barrel and earths gravity)

t=67.8, but this is only from when the bullet leaves the barrel to the apex of the curve so:

t=135seconds. TWO MINUTES of flight time.

Then assuming no wind drag you do distance=time*velocity:

d=940cos(45)m/s*135s

d=45078m

d=45 Kilometers. ~30 mi

Granted its been a while since I took Physics :D Correct my math if I'm wrong.

vf=vi-at

0=940sin(45)-9.8t (assuming SS109 projectile from a 20 in barrel and earths gravity)

t=67.8, but this is only from when the bullet leaves the barrel to the apex of the curve so:

t=135seconds. TWO MINUTES of flight time.

Then assuming no wind drag you do distance=time*velocity:

d=940cos(45)m/s*135s

d=45078m

d=45 Kilometers. ~30 mi

Granted its been a while since I took Physics :D Correct my math if I'm wrong.

TwoWheelFiend

January 10, 2012, 10:00 AM

lol thanks tyeo. I have to assume once you factor in drag and wind there is no way a .223 can go 30 miles.

alsaqr

January 10, 2012, 10:00 AM

Never really got into serious math stuff myself. The US Army says the maximum range of 5.56mm M193 ball ammo is 3,100 meters.

See page 172, Table B-1.

http://armypubs.army.mil/epubs/pdf/P385_63.PDF

See page 172, Table B-1.

http://armypubs.army.mil/epubs/pdf/P385_63.PDF

steveracer

January 10, 2012, 10:02 AM

3600 yards. According to the Navy.

lowerunit411

January 10, 2012, 10:03 AM

this is what ive always heard...the 223-5.56mm max range is 3,600 meters, the maximum effective range is 300 meters. dont know if it is accurate info or not actually.

1911Jeeper

January 10, 2012, 03:26 PM

Maximum (effective) range is different than maximum distance. The trajectory of a bullet must be factored into any calculations.

With the small-arms bullet, the effect of air resistance is so great that the maximum distance is obtained at an elevation of about 29°. There is little change as the gun is elevated to about 35°. At angles greater than 35° the bullet will begin to fall closer to the shooter.

If you can follow the math see this - http://www.worsleyschool.net/science/files/bullet/trajectory.html

Texas Park and Wildlife has a chart of distances bullets can travel for their hunter education safety course.

http://www.tpwd.state.tx.us/learning/hunter_education/homestudy/firearms/bullets.phtml

.

With the small-arms bullet, the effect of air resistance is so great that the maximum distance is obtained at an elevation of about 29°. There is little change as the gun is elevated to about 35°. At angles greater than 35° the bullet will begin to fall closer to the shooter.

If you can follow the math see this - http://www.worsleyschool.net/science/files/bullet/trajectory.html

Texas Park and Wildlife has a chart of distances bullets can travel for their hunter education safety course.

http://www.tpwd.state.tx.us/learning/hunter_education/homestudy/firearms/bullets.phtml

.

tyeo098

January 10, 2012, 03:30 PM

You have to factor that the OP asked about a 45 degree angle

http://www.craville.110mb.com/calculators/proj.htm

Find the Velocity on the wiki, plug in the angle, check the box for RANGE and hit submit.

http://www.craville.110mb.com/calculators/proj.htm

Find the Velocity on the wiki, plug in the angle, check the box for RANGE and hit submit.

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