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cc's to oz conversion table

Discussion in 'Handloading and Reloading' started by Grayrock, Apr 8, 2007.

  1. Grayrock

    Grayrock Well-Known Member

    Does anyone have a conversion table for the Lee dippers for weight of #8 shot they hold? For example, how many ounces does 3.1cc of shot weigh?
  2. Ol` Joe

    Ol` Joe Well-Known Member

    I know of no chart showing this, but I believe you should wgt it yourself on a scale to see. The size of the shot will make a difference as it will alter the density of the shot in the cup. #12 will likely wgt more then a scoop of # 5s.
  3. Grayrock

    Grayrock Well-Known Member

    Sorry Ol' Joe- but that helped like- none at all.

    I know of no chart either- hence my post. I don't have a scale- hence the post. I realize different shot will weigh differing amounts- hence my specifying #8 shot.

    Anyone else?
  4. HeedJSU

    HeedJSU Well-Known Member

    CC's and ML's (at least of liquids) are very very close

    IN liquids, there are 30 ml's (6 tespoons) in an ounce.

    So for instance,

    30 cc = 1 ounce
    60cc= 2 ounces
    90cc= 3 ounces.
    and so on.
    I don't know how that converts to the shot or the weights though
  5. Grayrock

    Grayrock Well-Known Member

    Problem here is ounce in this case is FLUID ounces=> volume.
    It is not ounces as a measure of weight. 2nd problem is that volume to volume conversion is actually pretty close- as long long as you are talking about water, which has a density of 1 gram per milliliter. I am asking about #8 LEAD shot- which has a different density than H2O.

    So I guess I still need help to answer my question.
  6. IDriveB5

    IDriveB5 Well-Known Member

    The density of lead is: 11.34  g/cm^3. Mass=(density)(volume). Then multiply by the number of shot. There are 28.35 grams in one ounce. Be sure to observe your units.
  7. CZ57

    CZ57 member

    IDriveB5: That is some sexy math, Now I'm excited except that there is no solution! Compounded a bit by the fact that the shot is spherical. Since I'm not the original barer of bad tidings, I'm afraid you have the conclusion Grayrock. You'll have to weigh the lead. CCs can of course be converted, but as a measure of volume. As far as ounces, there are 437.5 grains per ounce.;)
    Last edited: Apr 9, 2007
  8. Ol` Joe

    Ol` Joe Well-Known Member

    As a last resort give Lee a call. They make, or did years ago, an adjustable dipper for measuring shot that went with their little kit one used a hammer with to load. It may be a long shot but they might be able to help.
    Sorry I can`t offer more help.
  9. Mal H

    Mal H Administrator

    3.1 cc's of #8 shot weighs 280 grains (.64 ounce).

    I had a 3.1 cc Lee dipper and a bag of #8 - nothing like empirical data, eh?
  10. IDriveB5

    IDriveB5 Well-Known Member

    Well, the volume of a sphere is 4/3*pi*r^3, so all hed need to do is measure the diameter with his trusty caliper, which all reloaders have, right? :)
  11. RexDart

    RexDart Well-Known Member

    You might try Convert, a handy little freeware program for doing unit conversions:


    It's also possible, should the existing formulae be lacking, to enter one of your own under the custom tab.
  12. brickeyee

    brickeyee Well-Known Member

    Purchase a scale.
    You need it to reload safely anyway.
  13. CZ57

    CZ57 member

    IDriveB5: Absolutely nothing wrong with your premise! It's the variables that would concern me. Is shot spherical, or is it a sphere? Would the diameter be consistent enough to base radius on?

    Next question: what is the number of #8 shot in a 3.1 cc Lee dipper?:D

    Interesting exercise and I think you'd be close . . .

    Then again, the chances that you would get exactly 280 grains every time you weighed 3.1 cc of #8 shot with a LEE dipper, say ten times . . . like Captain Ramius said in The Hunt for Red October: "personally, I'd rate our chances no better than one in three."

    The law of averages is definitely a factor here.;)
  14. IDriveB5

    IDriveB5 Well-Known Member

    I would bet (some pocket change?) that the diameter of shot would be pretty consistent, especially if it is of high antimony. You could take a sample, measure them, calculate average, standard deviation and set up a confidence interval for the radius of the shot. I think you'd find that approximating each shot to be a sphere would be a reasonable approximation.

    Then, to be even more accurate, you'd have to account for the fact that most lead shot is 97% lead and 3% antimony (p=~6.6g/cc).

    So, now you have your weight of one #8 shot. All you have to do is count up your 262 #8s and you can multiply that by your weight for your individual shot. :D I'll pop the popcorn!

    I'm almost curious enough to open up a shell.


    Well, I got a little curious, so I opened up a shell, measured 25 #8s, made a couple assumptions and:
    Conclusion: Approximating shot to be a sphere is a fair, but not perfect assumption. But who the hell counts out their shot anyway?;)

    Grayrock- I'm sure you didnt expect all this debate when you posed a simple question, did you. I have to ask: you do have a scale, dont you?
    Last edited: Apr 10, 2007
  15. Grayrock

    Grayrock Well-Known Member

    You got that right.

    See post #3 above. I only load black powder and everything is done by volume.

    With all the time you took to measure 25 spheres of shot and create the spreadsheet for it, you could have been dippin' and weighin' instead. THEN I would have had an answer.
  16. Mal H

    Mal H Administrator

    You DO have an answer - that is if you didn't just skip over my post above.
  17. redneck2

    redneck2 Well-Known Member

    Mal H....never overlook the obvious :rolleyes:

    Amazing how many people look hard for an answer that's right in front of them

    Maybe if you'd say LOOK AT POST #9 they'd get it
  18. IDriveB5

    IDriveB5 Well-Known Member

    My reply was more in response to CZ's post, regaurding consistency in diameter:
    and not so on the topic of the original post.
  19. Grayrock

    Grayrock Well-Known Member

    Got it- thanks. Do you think a simple ratio calculation would work for the other sizes? I just used 3.1cc as an example. I am looking for a conversion table that would detail the capacity for all of the dippers.
    3.1cc DONE
    and last but not least- 4.3cc

    I appreciate your efforts. Better than the response I got from Lee- they told me to purchase the slide card (that I already have and that only details powder capacities- which was not what I asked them about.)

    Oh, and redneck2: that was kind of negative, don't you think?
  20. CZ57

    CZ57 member

    As far as I see it, Q&A ended in post #9. The component manufacturers are well aware of the differences likely to result in metering #8 shot.

    Nevertheless, I happen to believe that math does have its place in reloading. If one doesn't have an inclination to feel the same way, I understand that as well.

    IDriveB5, I applaud your tenacity in looking for a mathematical solution. What I'm seeing here is that you have 9 different diameters of shot in a sampling of 25. This is why I raised the question of diameter consistency for your original equation, especially since cubing radius is a factor. To make your original premise work, you would have needed at least an average of the nine diameters that also accounted for the deviation.

    Now, is the popcorn ready?

    "But who the hell counts out their shot anyway?" Well, the question I posed that resulted in you asking this, was a bit tongue in cheek, because some count would be necessary to establish at least an average diameter.;)

    There is a conversion chart and I believe I have it around here somewhere. I believe it was done by Winchester.

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