The 32 S&W Long wadcutter cartridge is the same length as the 32 S&W cartridge. I don't understand why you say that is a big no no. Please explain why it would not work.
The cylinder length is longer then the cartridge.
The Smith & Wesson Long cartridge does not used a heeled bullet. A heeled bullet is one where the front part of the bullet is the same diameter as the cartridge case, where the back part is stepped down so that it will fit inside the case. The best example I know of today is the .22 Long Rifle round. So, in revolvers the chamber is bored straight through.
However in modern day center-fire revolvers the chamber is bored with a step toward the front, where the back part is bored to fit the case, while the front part is reduced to fit the bullet. The bullet itself is the same diameter as the inside of the case, not the outside.
In the present instance, the .32 S&W Long case diameter is .337". The bullet diameter is .312". The back of the chamber is .3395", while the throat (small size) at the front where it is stepped down is .314".
If you were to bore the chambers straight through as you suggested, the larger diameter would be .3400" (give or take) where the bullet would only be .312", a difference of .028". (Or .014" to the side.) Not good at all.
Your proposed solution would work if the cylinder length was exactly the same as the .32 S&W long wadcutter cartridge, but then you would have to reduce the length of the cylinder, and you'd have an excessive cylinder/barrel gap.
Clear as mud?