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How accurate is your rifle at 34,000 yards?

Discussion in 'Rifle Country' started by Jenrick, Oct 5, 2008.

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  1. Jenrick

    Jenrick Member

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    Found an interesting article on naval guns. This is in reference to the 16"/50 Mark 7 guns on the Iowa class BB.

    http://www.navweaps.com/Weapons/WNUS_16-50_mk7.htm

    So if my math is right, this works out to .222 MOA?

    34,000 yards, means 1 MOA is 35604.7167406844 inches or 989.0199094635 yards, we'll round that to 990 yards. So a pattern of 220 yards is .222 MOA, not bad for a 15 rounds group. Smallest 8 group of 8 is .15 MOA, and the dispersion is .124 MOA.

    So the next time someone is saying that they can shoot a .25 MOA or smaller group at 1K+ yards, before you say it's BS, you might ask if he's using a battle ship :)

    Far as loadings go, how about a 13,300,000 gr (1,900 lbs) bullet if you like light and fast up to a 18,900,000 gr (2,700 lbs) if you believe in heavy and slower. Charges range from about 2,275,000 gr (325 lbs) for light practice loads, to 4,585,000 (655 lbs) for full power HD and hunting loads.

    Now time to find a bigger powder measure, as the Lee one I've got isn't going to meter those 2" long grains real well.

    Just found this interesting, especially the relative accuracy of the weapon over the range.

    -Jenrick
     
  2. jackdanson

    jackdanson Member

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    You really probably need one of these if you are hunting anywhere north of Iowa.
     
  3. General Geoff

    General Geoff Member

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    Big artillery guns will always be inherently more accurate in this sense, because gravity is more consistent than wind, which affects small arms projectiles far more profoundly than thousand plus pound projectiles.
     
  4. f4t9r

    f4t9r Member

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    not very accurate at that distance. I did however make a good shot at 34 yards.
     
  5. hankdatank1362

    hankdatank1362 Member

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    So, I found the OAL of the rounds... I guess the 16" refers to the diameter of the rounds? :confused:

    And, holy moly, 280-350 rounds barrel life? That sucks!
     
  6. Almond27

    Almond27 Member

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    eh, I hit can hit a deer halfway behind a tree at 35,000 yards with my .300 winchester magnum, with the wind blowing at 24mph east. Its true I have done it before.:neener:
     
  7. Jeff F

    Jeff F Member

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    A whole new meaning to the term 'long range snipping'.
     
  8. oneshooter

    oneshooter Member

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    At Iwo Jima the Marines would locate a cave and mark it with smoke. One of the BB's offshore would fire a single 14" 1200lb HE round at the cave. The Marines would call in corrections as needed. The BB's were only 10,000 yard offshore so the HE rounds would strike at about 2000fps! A 14" 1500lb round could penetrate 8ft or more of reienforced concrete!!

    The 250-350 round barrel life is using AP with full pressure charges.

    Oneshooter
    Livin in Texas
     
  9. gvnwst

    gvnwst Member

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    :what::what::what:

    where can i get one? do i have to regester it as a DD?:neener::p
    :D
     
  10. jerkface11

    jerkface11 Member

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    If you were using the Iowa class against modern warships you wouldn't need the AP rounds none of them would be able to take a single hit from an HE and survive. Plus the Battleships would be totally immune to anti shipping missiles.
     
  11. General Geoff

    General Geoff Member

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    I've always wondered about that, how effective any modern anti-ship weaponry would be against an Iowa.
     
  12. Disgruntled

    Disgruntled Member

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    "Big artillery guns will always be inherently more accurate in this sense, because gravity is more consistent than wind"

    eh, not to pick a nit, but you might be thinking of inertia, not gravity.
    Gravity is constant.
     
  13. W.E.G.

    W.E.G. Member

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    You think that's a trick.

    Don't forget about the trick of getting the outboard guns to fire simultaneously so they are not only accurate, but also so they don't rip the turret right off if fired out of sync.
     
  14. General Geoff

    General Geoff Member

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    Inertia is a constant as well. I'd say a perfectly constant law of physics is pretty consistent, don't you think?
     
  15. sarduy

    sarduy Member

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    good to go varmint hunting :D
     
  16. Jorg Nysgerrig

    Jorg Nysgerrig Member

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    The original version? Very. The refitted version? Not quite as much. You have to keep in mind that they reactivated the Iowa class ships in the 80s and modernized them.
     
  17. C-grunt

    C-grunt Member

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    I would think that a Tomahawk or similar type missile would do some serious damage to any ship. I would think that an anti-ship missile would have a warhead designed specifically for sinking boats.

    Didnt the British lose a ship in the Falkins (spelling) to a missile?
     
  18. Powderman

    Powderman Member

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    If you're curious about ASM and their relative effectiveness, look up some specs on the Silkworm, and most notably, the "Moskit" or "Sunburn" missiles.

    Remember, you don't have to SINK a ship to render it combat ineffective.
     
  19. aspade

    aspade Member

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    Yes and no. The protected parts of the ship - the main artillery, the magazines, the engineering spaces - would obviously be largely invulnerable to ASM warheads designed to destroy unarmored structure.

    But the eyes and ears of the ship above decks - all the more so the electronics refitted later - are as vulnerable as those on any other ship.

    USS South Dakota was soft killed at Guadalcanal by Jap 6 and 8" shells which are a lot less destructive than 700 lb Sunburn warhead.
     
  20. RecoilRob

    RecoilRob Member

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    Double check the math....

    Circumference of the circle @ 34,000yds = 3.1416x34000= 106814.4yds/360=296.707per degree 296.707yds/60=4.945 yds per minute

    Edit: Just tried my math on 100yds and something is wrong....so the above isn't correct. Man, it is late! For some reason, the above method seems to be half of what is should be...but I am unable to see why right now. Perhaps it can jog the correct answer from someone.

    Correct # is close to 29.75 feet. Math is funny sometimes when you cannot figure it out....
     
  21. Swampy

    Swampy Member

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    RecoilRob is correct.....

    1 MOA at 34k yards is somewhat on the order of 29-30 feet.... not 990 yards.

    Best to all,
    Swampy

    Garands forever
     
  22. Walkalong

    Walkalong Moderator

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    Mine won't reach that far. :( :uhoh: :rolleyes:
     
  23. Dr. Tad Hussein Winslow

    Dr. Tad Hussein Winslow member

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    13 million grains for the light n fast crowd - tee hee.
     
  24. DPStx

    DPStx Member

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    Math Problems.....

    Gotta love math, my calculations are thus.....

    Formula for circumference of a circle is C = 2piR or piD where R=radius, D=diameter.

    c= 2 x 34000 x pi = 68000 x3.14.... which = 213628yds circumference.

    divide this by 360 degrees and you get 593.4 yds per degree,
    divide this by 60 minutes per degree and you get 9.89 yds per minute of angle

    I believe this is one MOA at 34000 yds
     
  25. Coronach

    Coronach Moderator Emeritus

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    As aspade pointed out, there is a differnce between a hard kill and a soft (or mission) kill. A hard kill is a sunken (or badly crippled) ship. A mission kill is a ship that is damaged enough that it cannot complete its mission. Hard killing a modernized Iowa with missiles would be a difficult task. Soft-killing her would be easier.

    The real danger to the old battlewagons would be torpedoes and mines. Modern torpedoes don't run into the sides of ships like they did in WWII. They run under them and detonate beneath the keel. The Iowa class BBs are no better protected against this than any other ship.

    Mike
     
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