Steve2md
Member
If two loads with same bullet, one a hotter load than the other, hit two different deer of the same size in the same place, and both bullets expanded at the same rate, one exits the other side, the slower one doesn't, how can the bullet that didn't exit, transferred more energy to that deer?
it can't, since they were traveling at different speeds they had different amounts of energy to transfer.
Now, Take 2 loads with the same bullet WEIGHT, same loads, but one is of an expanding design and the other is not.
Everything else being equal, they will look, act, and perform the same on paper or steel targets, but in flesh, the expanding projo "should" remain in the hypothetical deer, while the other passes through. The permanent wound channel (and temp wound channel) of the expanding projectile will be larger in diameter, because of its "dump" of energy in a smaller space, causing more hydrostatic shock than the pass through. If there was no energy transfer other than that of the bullet itself, any wound channel would be the size of the projectile and no larger. We can see from ballistic gel tests and in field experience that this is not the case.
In the end though, none of this argument matters in the practicality of the situation. Pass a foreign object from outside of the body into an important part of the animal (Heart, Lungs, CNS) and they will go down, Pass through or not. For practicality, the mechanics of the thing aren't that important as long as you make a clean kill, right?
There is a new energy transfer thread started to shift it off of this thread for those who want to argue the matter, but in the end, a kill is a kill, right?
I'd like to request that a moderator move the energy transfer portions of this thread to the appropriate thread, so the OP can get the answers he's looking for without all the confusion.