Since everyone is concerned with power?

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^^ Not exactly. Although the diameter is 0.223, its shape is non-spherical, thus the .223 has a much greater volume. To compute the equivalent volume we need more dimensions than diameter. I'm not a .223 guy, anybody know the length of the actual bullet?

Alternatively, there are hydrodynamic masses for various geometries given in Patton (see below), which is unfortunately not a part of my personal library. If anybody has a copy, I'd love to get a PM.


Patton, K. T., "Tables of Hydrodynamic Mass Factors for Translational Motion," ASME Winter Annual Meeting, Paper 65-WA/UNT-2, 1965.
 
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unit91, are you modeling the whole bullet as a sphere in your example i.e. r (sphere) = ((bullet weight/density)*(3/4PI))^1/3?

:)
 
This may sell powerful cartridges, but is entirely evil. Hunters are encouraged to shoot at ranges beyond a reasonable hit probability given their lack of shooting skills. Animals are being hit, run off, and die a suffering death. Hunters should be encouraged to get as close as possible and hit that vital spot and get a clean kill

That is why i only bow hunt.. :) 20 yard shot and deer usually runs only 20 yards.. Last one i shot this past season ran only 15 yards.. Dropped in less than 2 mins after shot.
 
unit91, are you modeling the whole bullet as a sphere in your example i.e. r (sphere) = ((bullet weight/density)*(3/4PI))^1/3?

Yes, sir. I was actually going to use Abaqus to find the volume of the bullet instead of computing it, to eliminate any estimation errors. Also, as a "sanity check" on your numbers, go shoot an empty milk jug, and then shoot a full one and see if the hydrodynamic effect only adds 4%. :)
 
1858 Again, keep in mind the context of my original post.

1. Energy is conserved. Hydro effects do not add energy to the system; the penetrator enters with a given amount of kinetic energy, period. However, due to the incompressibility of water, blood, etc., any deformation occurs where compression is possible (such as organ tissue).

2. Also stated in my original post, these computations are WAY too complicated for by hand "back of the envelope" methods. Solving them requires use of the energy potential, as is common in the finite difference method employed in many computational fluid dynamics (CFD) packages. Furthermore, running a CFD job that could produce anywhere near accurate results would first require a validated structural model (which we don't have). A person could obtain at least two PhDs (structures and fluids) if he accurately characterized the above modeling requirements.
 
Prior to the advent of smokeless powder, weren't many big game animals taken with such "weak" rounds as the 44/40 and 38/40?

I mostly like to hunt with guns that are also fun to shoot. The exception being shotgun slugs, due to the fact I have a fascination with hurling massive chunks of lead down range at the expense of my shoulder.:D

For me, the ultra speedy mega magnums never made much sense. I hunt northern New England where the woods tend to be real thick, and you only get 50 yards of visibility, if you pick a good spot. I can't see how having a .338 Insanomag with a 40X scope on top would be a worthwhile investment to make 40 yard shots on whitetail:D. But, the beauty of America is that you can still mostly do what you want.
 
Well....Why shoot a 22.250 when a 22lr will kill prarie dogs? Because it's easier with the 22-250. Same answer with any mag type cartridge.
 
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