Mulling those two over, but 6000 RPM seems really really slow.
Consider a rifle with a muzzle velocity of 1000 feet per second and a one turn in 12" twist.
1 in 12 twist is one turn per foot.
1000 feet per second yields 1000 RPSecond
1000 RPSecond = 60,000 RPM
Even the stubby bullet out of a 1911 runs over 38,000 RPM. (16" twist, 850 f/sec)
60,000 X (12 ÷ 16" twist) X (850 feet per second ÷ 1000) = 38,250 RPM for the 1911 .45ACP RPM, if my arithmetic is correct.
EXTRA CREDIT:
Calculate the bullet RPM for a rifle firing it at 2900 feet per second with a 10 inch twist.
Hint:
Since this twist is faster than 1 in 12", the 60,000 RPM must be mutiplied by 12/10)
Since this velocity is faster than 1000 f/s, the 60,000 must be multiplied by 2900/1000
Thus:
60,000 X (12 ÷ 10) X (2900 ÷ 1000)
Back of book answer is 208,800 RPM
It is not out of line for a high velocity rifle bullet to hit a quarter million revolutions per minute.
For a long streamlined projectile, especially with the weight in the rear, 6000 RPM seems untenable.
Terry, 230RN
NOTE: The "Greenhill Formula" was only an approximation of the ideal twist for a given weight and diameter of bullet. The above numbers are not necessarily meant to imply "ideal" twists, but merely find the RPM for a given velocity and twist rate.