BlindJustice,
It is typical for most European (esp. German, Austrian) manufactured 9mm pistols to have a twist rate of 1 turn in 9.84 in. (~25 cm). Glocks, CZs, XDs and HKs have this rate of twist, IIRC.
The second and third generation S&W steel/aluminum framed semi-autos (3900s and 5900s) had a twist rate of 1 turn in 16 in. and I believe that the current crop of the S&W polymer framed M&P series also have this same rate of twist.
Typically, heavier (therefore longer) bullets require a faster rate of twist (spin) in order to stabilize them and lighter (shorter) bullets require less spin imparted to them from the rifling in order to achieve the gyroscopic stabilization necessary for balanced flight.
You can also use the Greenhill Formula to determine the minimum required rate of spin for a particular bullet weight (and length).
Since you may not have those lengths available to you, I've provided them from pulled FMJ ammunition (S&B 115 gr. and 124 gr.) and from pulled Hornady 147 gr. XTP "CQ" JHPs below:
"L" in inches for common, various 9mm bullets:
S&B 115 gr. FMJ: 0.590"
S&B 124 gr. FMJ: 0.608"
Hornady 147 gr. XTP JHP: 0.657"
The Greenhill Formula is:
150 (D²) ÷ L = length of minimum required twist in expressed in inches.
where D is the diameter in decimal inches of the bullet and L is the length of the bullet in decimal inches.
so for example:
A 9mm 147 gr. JHP having a diameter of 0.3545" and a length of 0.657" will need at least:
150 (0.3545"²) ÷ 0.657" = 1 turn in 28.6918 inches in order to be properly stabilized.
So you can see that even the longest 9mm bullets can/will be adequately stabilized by even the rifling pitch of 1:16 of the S&W autoloaders.
The 124 gr. FMJ would need a twist rate of at least 1 turn per 31.00 inches of travel in order to achieve proper gyroscopic stabilization.
Hope this helps you out,