I have a question concerning Richards No 1 conversions. I am a machinist and have been asked to build a conversion for a gentleman, the question I have is that when the hammer is in the down position (when being fired) was all of the hammer weight put on the firing pin? I know that some revolvers used a hammer stop and was curious about it. It would seem that the firing pin would take a heck of a beating with all the hammer inertia impacking it alone. I have the coversion ring finished and this is the last concern that I have.
Thanks
Thanks