Shawn Dodson said:When shooting up or down a steep ravine or hill, you have to determine the "level" distance between you to the target. This is why a bullet appears to hit "high" when fired uphill or downhill. The "level" distance is the distance that gravity acts on the bullet.
This is incorrect. The reason why a bullet drops less when fired at a target at an angle other than 0˚ and at the SAME distance away is that the component of g (gravity) perpendicular to the path of the bullet is LESS than g. For example, at an angle of 45˚, the vector component of g that is causing the bullet to drop relative to the point of aim is 0.707g. The figure below shows how to calculate the value of g using a 20˚ angle as an example. For all intents and purposes, a bullet's time of flight to a target X yards away at 0˚ is the same as the time of flight to the target X yards away at an angle of 45˚. Given enough decimal places this can't be true since the bullet fired horizontally has no g component acting opposite to the direction of the bullet's path. A bullet fired at a positive angle does have a component of g that is opposite to the direction of the bullet's path, however, velocity decrease due to -g is negligible compared to the bullet's velocity within practical ranges.
For example, consider an extreme but plausible situation encountered by a hunter. The hunter ranges a deer at 424 yards at an angle of +45˚. Against the advice of Sierra, he's using Federal Gold Medal Match 168gr BTHP ammunition. He has a ballistic table for FGMM 168gr (0˚) printed out in 25 yard increments taped to his stock. He looks at his table and sees that the bullet drop at 425 yards is 42.0". He remembers your post and you saying "The "level" distance is the distance that gravity acts on the bullet" [when shooting uphill or downhill] so he does a quick calculation using x = r*cosθ where x is the horizontal distance to the target (what you refer to as A-C) and r is the distance that he ranged (what you refer to as A-B). He calculates that the horizontal distance is 300 yards. So he looks at his ballistic table for the FGMM load and sees that with a 100 yard zero at an angle of 0˚ the bullet drop at 300 yards is 16.0". If he uses a 16" holdover, his bullet will hit 9" below what he's aiming at because the drop at 425 yards at +45˚is 25.0" and not 16.0".
The easiest way for a shooter to make corrections for long-range shots that are at significant positive or negative angles is to have a cosine indicator installed on their scope such as the one shown below. The indicator gives the shooter a number which is multiplied by the bullet drop at 0˚ at the range of interest. I don't know if the cosine indicator is as good as a ballistic table or if it simply gives a good enough estimate. In the example above, .707 * 42.0" = 29.7" whereas ExBal calculates the bullet drop to be 25.0". So merely multiplying the cosine of the shooting angle by bullet drop at 0˚ at the range of interest omits some variables.
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