Leaving semi-auto action open:

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Picture the following:

A home defense shotgun is a Remington 1100 with a deer barrel. The magazine has three shells. The action is open with one shell in the receiver.

If you need the weapon, you pick it up, press the button to close the bolt thus loading the gun.

Question: will leaving the bolt open like that create any problems for the shotgun? I know that used to you weren't supposed to keep springs suppressed because they would lose their tension. But metallurgy has come a long way.

Thanx.
 
I wouldn't do it. I don't see any reason to do it.

Put a shell in the chamber and the safety on, or leave the chamber dry and set an other round right next to the gun.
 
unless a spring is compressed beyond the point it is intended to be compressed, leaving it in such a state shouldn't hurt the spring, it is the constant working of the spring that causes it wear out.

It shouldn't hurt ths spring, however not sure how good an Idea it is to keep a gun in this state...
 
Won't hurt the springs, but I don't see the point of that ready state. Might as well just keep it loaded.
 
I wouldn't do that. Not for concern about the springs either.

This is not exactly a controlled round feed mechanism you're talking about here, leaving essentially a loose round rattling around inside the receiver while the gun is propped in a corner/hung on pegs whatever is not my idea of a wise thing to do. How good are the odds of that round misfeeding/jamming instead of feeding if it gets itself propped somewhere half crosswise in the action? Be fun trying to clear it in the dark, in a hurry.

If you are worried about getting the gun into action quickly, then load the round all the way into the chamber with the safety on and be done with it. Otherwise load the magazine, leave the chamber empty and let it go at that. Just be sure you know what state the gun is in and be careful.

lpl/nc
 
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