That is not what static stability means. Airplanes in flight have static stability, Rockets in flight have static stability, and bullets in flight have static stability.
Static stability in the case of bullets, it is the tendency of a bullet to remain in the attitude they were in at launch, ie not tumble. The spin of a bullet is what allows a bullet to have static stability.
Dynamic stability is the nature of a bullet's static stability with regards to perturbations to initial attitude.
If a bullet is statically unstable, it will tumble. If a bullet is statically stable, but dynamically unstable, the bullet will remain in stable flight until something, wind, a speck of dust, muzzle blast, anything, induces a yaw, and at that point the yaw will increase until the bullet departs stable flight. If a bullet is statically stable and dynamically stable, any yaw will be damped to zero.
A bullet flying through the air is never perfectly aligned longitudinally with the wind, the wind is never straight along the long axis of the bullet. For one, the bullet is moving forward and dropping at the same time, so it always has some angle relative to the wind. Anything moving in an asymmetrical airflow (it has an angle of attack, or in this case - yaw) over its surface will produce lift. That lift can be represented as a vector acting on a point in the body, that point is the center of pressure. The distance from the CG to the CP times the lift force perpendicular to the longitudinal axis of the bullet is the "over turning moment". The over turning moment will tend to push the nose of the bullet into greater yaw angles.
If the bullet has sufficient spin, the gyroscopic moment will push the nose so as to reduce the yaw, it is statically stable.
Here is a primer on exterior ballistics.
By the way, a round ball has a CG and CG in the same place, the center of the ball, and is statically neutral, neither stable or unstable. If you design a projectile with the CP behind the CG, and arrow with the fletching at the rear, it will be stable without the need to spin it, but still might be dynamically unstable.