1 MOA means a target circle how big at 100 yrds?

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This is a fun discussion.
I have to agree with Blackrazor on this one. I think the confusing point here is that there are three ways to quantify how far off a shot is. The first is to describe the angle the bullet traveled compared to the intended travel vector. This is Measured in minutes or degrees if you are a lousy shot. Another way is to measure the arc length of a circle at a given distance. The third and most widely used is to measure the distance of deviation of the shot in the plane which the flat 2 dimensional target defines. We are defining the distance of a miss as the distance from the bullseye to where the bullet reaches a plane extending from the 2 dimensional target hanging at 100 yards. This is the common "group" measured in inches. For all practical purposes, arc lenght and group size are interchangable for small angles (few degrees) and group size and arc lenght may be converted into MOA by a simple multiplication factor. Error becomes significant when you are many degrees off target.

The reason I like blackrazor's point of view is because in the real world, we don't directly measure angle or arc length, we measure group size in the plane of the target. Therefore it is appropriate to use a fixed adjacent side of 100 yards and a measured opposite side (shot deviation from bullseye). These are the only values we know. from there we must calculate the angle. The arc lenght can also be calculated from this.

As far as the infinite miss, he is not saying that 90 degrees is an infinite quantity of course. He is saying that a bullet aimed at the center of a plane which is fired 90 degrees off target will never stike the plane. So in the 90 degree miss, the angle is 90 degrees, the arc length is 157.08 yards. Since the bullet will never strike the plane of the target, the measured deviation in that plane is infinite.
 
Anyhow, I imagine you'll have a long and illustrious career at one of the spice companies, picking fly poop out of pepper.

I almost fell off my chair there! :D
 
Ditto on that Daniel.

Art... funny, sometimes I *do* feel like that is my career. I guess you had me pegged :eek:


thanks for backing me up, No4Mk1. Looks like we're on the same page.
 
Ya'll got it all wrong! Einstein said that relative velocity distorts both time and space. Therefore, the bullet actually never reaches the target....:evil: :evil:
 
Well, the bullet does reach the target, but it will be a bit "younger" than it would have been if you walked it there. heh heh
 
Let me wade in on one point: 90 deg being an infinite circle at 100 yrds.

I think when you are looking at these large angles, think of them as +- 45 degrees, not 0 to 90. If I aim 45 degr off to the left of the target, I will hit at 100 yrds on the side of the target (think of a 45 degree triangle). If I now aim 45 to the right of the target, and again hit 100 yrds to the side.

The two holes in the target are now 200 yrds apart (-45 and +45 degr from my POV), which is in the neighborhood of 7200 MOA!

Everybody got it?
 
Dave,

yes, I see what you are saying. When I said 90 degrees off, I meant in one direction, or +/- 90 degrees. You can also just think of it as 180 degrees (by your definition), which of course still implies "infinite" missing of the target.

But, from looking at your example of +/- 45 degrees, the error in the statement "each MOA is 1 inch at 100 yards" really becomes obvious. As you said, the two holes in the target are separated by 7200 *inches* (i.e. 200 yards), even though there are actually fired 5400 *MOA* apart! So clearly at increasingly large angles, each additional minute of angle corresponds to much more than 1 inch at 100 yards.

whew.

P.S. I guess I'm a freak...but y'all are too if you've read this far! :neener:
 
?

Nothing wrong with a little mental exercise, I think this stuff is fun. Keeps the mind sharp....

:cool:
 
Well, I might as well step in and add my .00000002 cents.

1 MOA @ 100 yds = tan (1/60)*3600 is not quite the right formula in this context.

It is a matter of definition in target group sizes calculations that the center point (what we might for convenience refer to as 0 MOA) is a calculated average of all distances measured center to center between each bullet hole and every other bullet hole considered. Thus, if I had exactly two holes in a target the center point (0 degrees) would be exactly half way between them. If then these two holes measured exactly 1 MOA from 100 yards distant, the deviation from 0 MOA would then actually be 1/2 MOA and so the correct formula for determining the precise distance in inches between the two points is 2*(tan(1/120)*3600).

2*(tan(1/120)*3600) <> tan (1/60)*3600

and that's my .00000002 cents :)

tstr
 
Good insight there, shootin' buddy. You are certainly right, because if someone says their rifle shoots 1 MOA groups at 100 yards, they usually mean that they can keep their shots within a 0.5 MOA radius circle around the center of the target. And, if there's one thing we've shown in this thread, it's that at any given distance, 2 x (0.5 MOA) does *not* equal 1 MOA. Your 20 nanocents are appreciated! :D
 
Yeah, closer to .0000000221524 or thereabouts. ;)

pax

There are three kinds of researchers: Those who can do math and those who cannot. -- Tom Rusk Vickery
 
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