The Real Hawkeye
member
I came across a lone .44 Special round in my drawer. Since I already had my S&W .45 ACP revolver out, just for kicks I thought I'd try putting it in the cylinder. I figured it would fall in, but lo and behold, due to the narrowing of the chamber past .45 ACP case length, it fit in like it was made for it, nice and snug, perfectly centered and, due to the rim, to the right depth. Tried closing the cylinder, and it closed no problem. The tip of the bullet was just short enough not to protrude out the front. Then it occurred to me, just hypothetically (I would never take the chance of damaging my new toy), what would happen if I fired it. Would it just pass harmlessly through at low velocity due to the space left by the undersized bullet (The "windage" as muzzle loaders call it), or would it do some kind of damage due to bouncing around against the barrel's interior surface, or even damage the forcing cone before it even got to the bore? Certainly the case would experience some sort of fire-forming process, but would the sudden expansion of the casing inside the undersized rear 65% of the chamber cause a rupture of the cylinder? Anyone know?