Ditchtiger
Member
Is nobody going to mention what happens if a window gets shot out of an airliner?
All glocks look the same
3: Bullets make sparks when they hit steel, concrete or other hard surfaces.
Anyone who has a passion for football, baseball, basketball, soccer, golf, hockey, NASCAR, etc. is a fan. Anyone with a passion for shooting sports is a "fanatic" and must be slightly unstable to have such interests.
Skywar said:The 30-30 is the most versatile rifle round EVER created
Kung Fu is better because you can pull the slide off a handgun before the shooter can react and pull the trigger.Karate is a viable defense against a firearm.
Now, copper and lead should not spark, so my guess is that the inpact of the bullet was causing rock fragments to spark off the side of the rock. The point is, make in impressive light show in the late evening.
Newton's Laws apply here, but what is conserved is momentum. The momentum of the bullet as it leaves the barrel and the momentum of the recoiling firearm are equal, minus whatever was soaked up by the action. However, momentum is equal to mass times velocity; kinetic energy is equal to one half mass times the velocity squared, so the much higher velocity of the bullet grants it disproportionate kinetic energy, even though the gun is heavier.
Here's an example: Suppose we have a 32 oz. revolver (using a revolver to avoid the issue of a semi-auto action absorbing some momentum) shooting 125-grain projectiles at 1400 fps. To keep the units consistent, let's convert the revolver's weight to grains: 32 oz = 2 lbs x 7000 grains / 1 lb. = 1,400 grains.
First we get the momentum of the projectile:
p = m * v --> p = 125 grains * 1,400 fps --> p = 175,000 grains * ft/sec
Momentum will be equal and opposite, so we plug that into the momentum equation for the gun to get the gun's recoil velcity:
p = m * v --> 175,000 grains * ft/sec = 14,000 grains * v --> 175,000 grains / 14,000 grains = v ft/sec --> v = 12.5 ft/sec
Since we have the masses and velocities of both bullet and gun, we now drop them into the equations for kinetic energy:
KE = 0.5 * m * v^2
KE(bullet) = 0.5 * 125 grains * 1,400^2 ft/sec --> KE(bullet) = 0.5 * 125 grains * 1,960,000 ft/sec = 122,500,000 grains * ft/sec
KE(gun) = 0.5 * 14,000 grains * 12.5^2 ft/sec --> KE(gun) = 0.5 * 14,000 grains * 156.25 ft/sec --> KE(gun) = 1,093,750 grains * ft/sec
Hope that helps clear things up.
I'd argue that shot placement is more important as long as you get a basic minimum of penetration.Molon Labe said:"For handguns rounds, bullet expansion is the most important factor when it comes to lethality." (Not true. Depth of penetration is the most important factor.)
razorburn said:But you can't prove something by doing an equation based off that what you're trying to prove is true.