410, but in a gauge

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TSchwab25

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Hey there people of THR, what gauge would a 410 actually be if it was measured in "gauges"?
 
From when black powder and card/felt wads ruled. They aren't as flexible as progressive smokeless powder and plastic shotcups, so a substantial change in loads meant a different gauge to balance velocity and pattern.
 
Yep and when Academy had them the Fed Top Gun was $1 higher than the Winchester AAHS
 
JimWatson said:
MEHavey said:
"Gauge" = Balls/lb
.410 ball weighs 103.4gr
7000gr/lb ÷ 103.4 gr/ball = 67.7 balls/lb = 68 "gauge"
Mathematically correct.
But the present Skeet load is 1/2 oz, so it is ballistically a 32 ga.
I say again... "Gauge" = Balls/lb
a "12" gauge barrel is ~0.73" diameter (think also Brown Bess)
a 0.73" lead round ball weighs ~586gr
7,000 gr/lb ÷ 586 gr/ball = "12" gauge
 
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That may be the reason for the old “16 gauge, 1 Oz load is the perfect combo” comments I’ve seen from days past.

Dont know if any of that is true, but I love the 16 and it’s fun to talk about. :thumbup:

This wiki page has a neat chart for calculating gauge, pounds, bore diameter in mm and in inches ranging from a 4-pounder (2.65”) down to the .410 bore. It’s a wiki, so take it with a grain of salt.

Stay safe.
 
So, Dr Science, what gauge is my .22 Stevens?

index.php


Todd.
 
Volume of sphere: 4/3 * pi * r^3 = 4/24 * pi * d^3 = 1/6 * pi * d^3
Density of lead: 11.34 g / cm^3
0.410" in cm: 1.0414 or so
1lb in g: 453.6g

453.6 * 6
_________________ = 67.64 gauge

pi * 1.0414cm^3 * 11.34


or simplified further...

76394.4
__________ = gauge

(bore in mm)³
 
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