I have been pondering this same question: So I ran some numbers by my ballistics program.
1. Assume a AR-10 size rifle with a 20 inch barrel.
2. Next step figure which loads would represent the loads likely to be used and which are different enough from each other.
3. What is the real velocity obtained by those loads with a 20 inch barrel.
So I went with:
6mm (243 Win) using a 95 grain boat-tail bullet with a MV of 3,000 fps. 0.480 B.C.
6.5mm (260 Rem) using a 120 grain boat tail bullet at 2,800 fps, 0.450 BC
7.62mm (308 Win) using a 150 grain Boat tail at 2,650 fps,, 0.398 BC
All zeroed for 300 yards.
The 243 is 4.6 inch high at 175 yards when zeroed at 300.
the 260 is 5.5 inch high at 150 yards when zeroed at 300
the 308 is 6.5 inches high at 150 yards when zeroed at 300.
Remaining velocity at 500 yards:
243 = 2,100 fps
260 = 1.887 fps
308 = 1,670 fps
NOTE*** Bullets which have not been over stabilized are capable of tumbling upset type devastating wounds at impact velocities around 2,600 fps and above.
243 = 2,600 fps impact velocity at 200 yards
260 = 2,600 fps impact at 100 yards.
308 = 2,600 fps at 50 yards.