Any idea how much 223 brass it takes to fill a 5 gallon bucket?

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Balrog

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I have resized, trimmed, and chamfered a 5 gallon bucket of 223 brass, and have no idea how many pieces that would be. Does anyone have a guesstimate?
 
Balrog, Do you have the empty bucket weight and the full bucket weight ?
 
Yep weigh it to figure it out. You can cram 809 into a 1 gallon ziplock bag...


9mm, 59.46gr/ea, 117.7cases/#, 8.5#/1000

38spl, 68.06gr/ea, 102.8cases/#, 9.7#/1000

40s&w, 70.1gr/ea, 99.9cases/#, 10#/1000

.357mag, 78.3gr/ea, 89.4cases/#, 11.2#/1000

.45acp, 89.58gr/ea, 78.1cases/#, 12.8#/1000

.223, 95.28gr/ea , 73.5cases/#, 13.6#/1000

.44mag, 114.38gr/ea, 61.2cases/#, 16.3#/1000

50bmg, 865.26gr/ea, 8.1cases/#, 123.5#/1000

All weights are uncleaned fired cases with the primer remaining.

Individual case weights were derived using an average of mixed brass weights (except 50bmg)

So, if you picked up 8#'s of 45 brass: 8# X 78.1cases/# = 625 cases+/-

If you use 1gal ziploc freezer bags to store your brass, each (full) bag contains:

9mm, 15.6#, 1836cases
40s&w, 12.2#, 1219cases
45acp, 11.4#, 890cases
223, 11#, 809cases

or if you use the 5gal bucket method

9MM = 8500-9000 pieces
.40 S&W = 7000-7500 pieces
.45 ACP = 3800-4000 pieces

here is a few more


CASES per POUND:

.380: 145
.357 Sig: 96
.45 GAP: 86
.32: 168
10mm: 96
FN 5.7: 124
.25 acp: 260
.30 Luger: 120
.38 S&W: 120
.38 Super: 104
9mm MAK: 124
.45 Colt: 60
.30-M1: 100
.308: 40
.30-06: 35
7.62x39: 54
.50 AE: 48
.30-30: 52
__________________
 
I'm not sure how many fit in a five gallon bucket.

But since you have them all prepped send them my way and I'll count them for you.

jim
 
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