lysanderxiii
Member
3.5 would round up to 4 rounds per engagement.An Average is calculated by dividing the sum of the values in the set by their number. So some of the values will be higher and some will be lower than the mean number.
For example; If 12 shooters fire 6 rounds and 12 shooters fire 1 round each then the average mean number is 3.5 rounds (12 x 6 + 12 x 1 = 84. 84 divided by 24 = 3.5).
In this simple example notice that to arrive at the sum of 3.5 rounds none of the shooters fired 3 rounds. They all either fired 1 round or 6 rounds. Since your Internet buddy does not believe in carrying 6 rounds then he is carrying 2 rounds too many according to the sample.
Assuming the number cited was correct, for the average to be 3 rounds there would have to be more single shot engagements than 6 shot engagements. Now if you factor in some people actually carry 7 to 15 rounds in the weapon, and in some cases actually shoot all of them, the number of 1 or two shot engagements would increase in inverse proportion to the number of 7 to 15 round engagements.
In your example, if we assume that one of your 12 people carried a Glock 17 and emptied the magazine in one engagement, then 9 of the remaining 11 engagements would have to be one shot affairs.
[(1 shot x 9) + (6 shots x 2) + (17 shots x 1)]/12 = 3.167
So, if this 3 round average number is true, then an overwhelming number of engagements must consist of only one round fired. To use the proper statistic term, the mode must be 1.
Barney was right, one round will do.
This also makes me feel better about the marksmanship of CCW permit holders, in that most time only one shot was needed to end the problem.