svtruth
Member
The distance of visibility
for a height of eye above the water of 6 feet is 2.8 miles, if you add another mile for the height of eye in the hypothetical kayak you get about 4 miles. A 9mm probably would not make it but a 30-06 might. Now if the kayaker's head is (let's say) a foot in diameter so at the ~7000 yds it is about .17 moa. I'm not sure I could see it, even though it is technically in view.
The formula is 1.17 times the square root of the height of eye in feet is the distance in miles. You add the distance for height of eye and the distance for height of the object to come up with the total distance.
Now, does anyone have experience shooting over smooth ice?
for a height of eye above the water of 6 feet is 2.8 miles, if you add another mile for the height of eye in the hypothetical kayak you get about 4 miles. A 9mm probably would not make it but a 30-06 might. Now if the kayaker's head is (let's say) a foot in diameter so at the ~7000 yds it is about .17 moa. I'm not sure I could see it, even though it is technically in view.
The formula is 1.17 times the square root of the height of eye in feet is the distance in miles. You add the distance for height of eye and the distance for height of the object to come up with the total distance.
Now, does anyone have experience shooting over smooth ice?
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